Consider deleting zero or more vertices of T T and the edges adjacent to them so that the remaining graph becomes a single Snowflake Tree. Find the minimum number of vertices that …

Here, N- (1+x+xy) N −(1 +x+xy) vertices need to be removed. The problem can be solved by iterating through u u and x x exhaustively, counting the number of vertices to be removed, and …

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Fix a vertex u u to become the center, and the number of first-layer vertices x x. If vertices v_1, v_2, ..., v_x v1,v2,...,vx are chosen for the first layer, the maximum value that can be chosen …

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先写上A~E的题解，后续补题会将F补上去思路：由题可知最多只能分成三组，我们只需要判断是否三个数都相等，或者两个数相加等于另外一个数即可。

頂点数 N N の木が与えられ、いくつかの頂点を削除して「ユ木」にしたい。 削除する頂点の個数の最小値を求めよ。 与えられた木において、どの頂点を「ユ木の中心」にするかで場合 …

E - Snowflake Tree 可以发现，确定中心点 u u 以及 x x 后，此时雪花树的顶点个数也就确定了，为 (min v deg (v)) × x + 1 (vmindeg(v))×x+1，其中 v v 是与 u u 邻接的点。

cout << "Yes" << endl; return 0; } if(a + b == c || a + c == b || b + c == a){ . cout << "No" << endl; return 0; } 解法. cin >> h >> w >> x >> y; . x --; . y --; . vector <vector <char>> S(h, …

省流：EF全挂 A 题意 是否能将三个数分成大于1组，使得每组总和相同 做法 直接判断 代码